Here is the answer for the question – **A 1.00 kg ball is thrown directly upward with an initial speed of 16.0 m/s.**. You’ll find the correct answer below

### A 1.00 kg ball is thrown directly upward with an initial speed of 16.0 m/s.

A graph of the ball’s gravitational potential energy vs. height, Ug(h), for an arbitrary initial velocity is given in Part A. The zero point of gravitational potential energy is located at the height at which the ball leaves the thrower’s hand.

For this problem, take g=10.0m/s2 as the acceleration due to gravity.

**The Correct Answer is**

**h=12.8 E=128Jbased on the kinematic equations:-vfi^2=vi^2+2ad( among the 4 available see notes)Etotal=KE+PE=0+mgh= (1kg)(10m/s^2)(12.8)=128J**

### Reason Explained

h=12.8 E=128Jbased on the kinematic equations:-vfi^2=vi^2+2ad( among the 4 available see notes)Etotal=KE+PE=0+mgh= (1kg)(10m/s^2)(12.8)=128J is correct for A 1.00 kg ball is thrown directly upward with an initial speed of 16.0 m/s.

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