A turntable has a moment of inertia of 3.00 102 kgm2 and spins freely on a frictionless bearing at 25.0 rev/min. A 0.300-kg ball of putty is dropped vertically onto the turntable and sticks at a point 0.100 m from the center. What is the new rate of rotation of the system?

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Here is the answer for the question – A turntable has a moment of inertia of 3.00 102 kgm2 and spins freely on a frictionless bearing at 25.0 rev/min. A 0.300-kg ball of putty is dropped vertically onto the turntable and sticks at a point 0.100 m from the center. What is the new rate of rotation of the system?. You’ll find the correct answer below

A turntable has a moment of inertia of 3.00 102 kgm2 and spins freely on a frictionless bearing at 25.0 rev/min. A 0.300-kg ball of putty is dropped vertically onto the turntable and sticks at a point 0.100 m from the center. What is the new rate of rotation of the system?

The Correct Answer is

22.7 rev/min

Reason Explained

22.7 rev/min is correct for A turntable has a moment of inertia of 3.00 102 kgm2 and spins freely on a frictionless bearing at 25.0 rev/min. A 0.300-kg ball of putty is dropped vertically onto the turntable and sticks at a point 0.100 m from the center. What is the new rate of rotation of the system?

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