Given the half-reactions and their respective standard reduction potentials.

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Given the half-reactions and their respective standard reduction potentials.
1. Cu3+ + 2e- = Cu+ Ei= +1.28 V
2. Cu2+ + e- = Cu+ Ei= +0.15 V
3. Cu2+ + 2e- = Cu Ei= +0.34 V
4. Cu+ + e- = Cu Ei= +0.52 V
Calculate the standard reduction potential for the reduction half-reaction of Cu(III) to Cu(II). Cu3+ + e- = Cu2+

The Correct Answer is

We can rearrange the equation delta G naught final = -nFE naught final to solve for E naught final:E naught final = – delta G naught/nFE naught final = -0.15 V – 2(1.28 V)/1 = 2.41 V

Reason Explained

We can rearrange the equation delta G naught final = -nFE naught final to solve for E naught final:E naught final = – delta G naught/nFE naught final = -0.15 V – 2(1.28 V)/1 = 2.41 V is correct for Given the half-reactions and their respective standard reduction potentials.

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