# Given the half-reactions and their respective standard reduction potentials.

Here is the answer for the question – Given the half-reactions and their respective standard reduction potentials.. You’ll find the correct answer below

### Given the half-reactions and their respective standard reduction potentials. 1. Cu3+ + 2e- = Cu+ Ei= +1.28 V 2. Cu2+ + e- = Cu+ Ei= +0.15 V 3. Cu2+ + 2e- = Cu Ei= +0.34 V 4. Cu+ + e- = Cu Ei= +0.52 V Calculate the standard reduction potential for the reduction half-reaction of Cu(III) to Cu(II). Cu3+ + e- = Cu2+

The Correct Answer is

We can rearrange the equation delta G naught final = -nFE naught final to solve for E naught final:E naught final = – delta G naught/nFE naught final = -0.15 V – 2(1.28 V)/1 = 2.41 V

### Reason Explained

We can rearrange the equation delta G naught final = -nFE naught final to solve for E naught final:E naught final = – delta G naught/nFE naught final = -0.15 V – 2(1.28 V)/1 = 2.41 V is correct for Given the half-reactions and their respective standard reduction potentials.

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