How do you ” find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches ?”

Answer for Question How do you ” find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches ?”. is given below:

Q.) How do you ” find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches ?”

Correct Answer is

Well if the perimeter is 28 inches, each side of the square is 7 inches. 28/4 = 7 because all sides of a square are the same.If we split the square in half to create 2 triangles we can find the length of the diagonal. The two sides are the bases of 7 inches.Use the Pythagorean theorem to solve for the hypotenuse or the diagonal.7^2 + 7^2 = diagonal ^ 2Therefore, the diagonal equals 9.9 inches.

Conclusion:

This correct answer to this statement is Well if the perimeter is 28 inches, each side of the square is 7 inches. 28/4 = 7 because all sides of a square are the same.If we split the square in half to create 2 triangles we can find the length of the diagonal. The two sides are the bases of 7 inches.Use the Pythagorean theorem to solve for the hypotenuse or the diagonal.7^2 + 7^2 = diagonal ^ 2Therefore, the diagonal equals 9.9 inches..

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