Here is the answer for the question – Suppose that you massed out 3.50 g of sodium carbonate (Na2CO3). How many moles would you have?. You’ll find the correct answer below
Suppose that you massed out 3.50 g of sodium carbonate (Na2CO3). How many moles would you have?
Hint: What is the molar mass of sodium carbonate.
The Correct Answer is
3.50gNa 2 CO 3 x 1moleNa 2 CO 3 / 105.99gNa 2 CO 3 = 0.0473moleNa 2 CO 3
Reason Explained
3.50gNa 2 CO 3 x 1moleNa 2 CO 3 / 105.99gNa 2 CO 3 = 0.0473moleNa 2 CO 3 is correct for Suppose that you massed out 3.50 g of sodium carbonate (Na2CO3). How many moles would you have?
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