Here is the answer for the question – **Suppose that you massed out 3.50 g of sodium carbonate (Na2CO3). How many moles would you have?**. You’ll find the correct answer below

### Suppose that you massed out 3.50 g of sodium carbonate (Na2CO3). How many moles would you have?

Hint: What is the molar mass of sodium carbonate.

**The Correct Answer is**

**3.50gNa 2 CO 3 x 1moleNa 2 CO 3 / 105.99gNa 2 CO 3 = 0.0473moleNa 2 CO 3**

### Reason Explained

3.50gNa 2 CO 3 x 1moleNa 2 CO 3 / 105.99gNa 2 CO 3 = 0.0473moleNa 2 CO 3 is correct for Suppose that you massed out 3.50 g of sodium carbonate (Na2CO3). How many moles would you have?

Thankyou for using answerout. We hope you get all your answers here. If you have any special questions, you can comment to ask us.

Latest posts by Alex Timmons (see all)

- Bromine, which has an atomic mass of 79.904 amu, has only two naturally occurring isotopes ( Br-79 and Br-81 ). The mass of Br-81 is 80.9163 amu, and its natural abundance is 49.31%. - March 8, 2023
- A substance applied to cuttings to speed up the development of roots is: - March 8, 2023
- Suppose that you massed out 3.50 g of sodium carbonate (Na2CO3). How many moles would you have? - March 8, 2023