Here is the answer for the question – **suppose you analyze a sample of fertilizer by the procedure of the experiment and obtain 1.000g of MgNH4PO4x6H2O as the product. Calculate the equivalent mass of P2O5 initially in the sample.**. You’ll find the correct answer below

### suppose you analyze a sample of fertilizer by the procedure of the experiment and obtain 1.000g of MgNH4PO4x6H2O as the product. Calculate the equivalent mass of P2O5 initially in the sample.

**The Correct Answer is**

**1.000g(1mol/245.24g)x (1molP/1mol)x(1mol P2O5/2molP)x (141.94g/1molP2O5)=0.289389985g=0.289g**

### Reason Explained

1.000g(1mol/245.24g)x (1molP/1mol)x(1mol P2O5/2molP)x (141.94g/1molP2O5)=0.289389985g=0.289g is correct for suppose you analyze a sample of fertilizer by the procedure of the experiment and obtain 1.000g of MgNH4PO4x6H2O as the product. Calculate the equivalent mass of P2O5 initially in the sample.

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