Tetraethylammonium (TEA) blocks voltage-gated K+ channels such that K+ cannot pass even when the channels are open. However, TEA leaves K+ leakage channels largely unaffected. How would you expect the action potential to change if you treated a neuron with TEA?

Here is the answer for the question – Tetraethylammonium (TEA) blocks voltage-gated K+ channels such that K+ cannot pass even when the channels are open. However, TEA leaves K+ leakage channels largely unaffected. How would you expect the action potential to change if you treated a neuron with TEA?. You’ll find the correct answer below

Tetraethylammonium (TEA) blocks voltage-gated K+ channels such that K+ cannot pass even when the channels are open. However, TEA leaves K+ leakage channels largely unaffected. How would you expect the action potential to change if you treated a neuron with TEA?
A. The membrane would depolarize as usual but then stay at that depolarized voltage (about +30 mV).

B. The action potential would depolarize as usual, but the repolarization phase would take longer, causing the action potential to be more broad in time.

C. The membrane would depolarize and repolarize as usual, but no hyperpolarization beyond (more negative to) the resting membrane potential would occur.

D. The action potential would fail. Once the voltage reached threshold, it would return to the resting membrane potential.

The Correct Answer is

B. The action potential would depolarize as usual, but the repolarization phase would take longer, causing the action potential to be more broad in time.

Reason Explained

B. The action potential would depolarize as usual, but the repolarization phase would take longer, causing the action potential to be more broad in time. is correct for Tetraethylammonium (TEA) blocks voltage-gated K+ channels such that K+ cannot pass even when the channels are open. However, TEA leaves K+ leakage channels largely unaffected. How would you expect the action potential to change if you treated a neuron with TEA?

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