Here is the answer for the question – Visible light falls into wavelength ranges of 400-700 nm, for which. You’ll find the correct answer below
Visible light falls into wavelength ranges of 400-700 nm, for which
1 m=1×109 nm1 m=1×109 nm. The energy and wavelength of light are related by the equation E=hc/λwhere
E is energy in Joules,
h is Planck’s constant (6.626×10−34 J-s6.626×10−34 J-s ), c is the speed of light (
2.998×108 m/s2.998×108 m/s
), and λ is the wavelength in m.
If a visible light photon has a wavelength of 669.8 nm, what is the energy of the photon (in J)?
The Correct Answer is
2.966e-19Convert the wavelength from nanometers to meters using the relationship that1 m=1×109 nm. λ in m=669.8 nm×(1 m/1×109 nm)Then substitute the wavelength into the equation.E=hc/λ=(6.626×10−34 J-s)(2.998×108 m/s)/ λ in m
Reason Explained
2.966e-19Convert the wavelength from nanometers to meters using the relationship that1 m=1×109 nm. λ in m=669.8 nm×(1 m/1×109 nm)Then substitute the wavelength into the equation.E=hc/λ=(6.626×10−34 J-s)(2.998×108 m/s)/ λ in m is correct for Visible light falls into wavelength ranges of 400-700 nm, for which
