What is the freezing point (in degrees Celcius) of 4.11 kg of water if it contains 191.8 g of

Here is the answer for the question – What is the freezing point (in degrees Celcius) of 4.11 kg of water if it contains 191.8 g of. You’ll find the correct answer below

What is the freezing point (in degrees Celcius) of 4.11 kg of water if it contains 191.8 g of
CaBr2? The freezing point depression constant for water is 1.86oC/m and the molar mass of CaBr2is 199.89 g/mol.

The Correct Answer is

-1.30calculate the moles of solute from the mass and molar mass of the solute and divide by the mass of water in kilograms.Substitute these values into the equation for freezing point depression.ΔTf=3×1.86∘C/m×m

Reason Explained

-1.30calculate the moles of solute from the mass and molar mass of the solute and divide by the mass of water in kilograms.Substitute these values into the equation for freezing point depression.ΔTf=3×1.86∘C/m×m is correct for What is the freezing point (in degrees Celcius) of 4.11 kg of water if it contains 191.8 g of

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